Root locus for L(s)=1/(s(s+1)(s+2))
Control Systems
Example from the compendium of canonical charts
Python Code
"""Control Systems — Root locus for L(s)=1/(s(s+1)(s+2))."""
import numpy as np
import plotly.graph_objects as go
def generate():
K_values = np.linspace(0, 30, 3000)
roots_real = []
roots_imag = []
k_colors = []
for K in K_values:
# Characteristic polynomial: s^3 + 3s^2 + 2s + K
coeffs = [1, 3, 2, K]
roots = np.roots(coeffs)
for r in roots:
roots_real.append(r.real)
roots_imag.append(r.imag)
k_colors.append(K)
fig = go.Figure()
# Root locus colored by K
fig.add_trace(go.Scatter(
x=roots_real, y=roots_imag,
mode="markers",
name="Root locus",
marker=dict(
color=k_colors,
colorscale="Viridis",
size=2,
opacity=0.6,
colorbar=dict(title="K", thickness=14, len=0.7),
),
hovertemplate="Re=%{x:.3f}, Im=%{y:.3f}<extra></extra>",
))
# Open-loop poles at s=0, -1, -2
fig.add_trace(go.Scatter(
x=[0, -1, -2], y=[0, 0, 0],
mode="markers",
name="Open-loop poles",
marker=dict(color="red", size=12, symbol="x", line=dict(width=2.5)),
hovertemplate="%{x:.0f}+j%{y:.3f}<extra>OL pole</extra>",
))
# Imaginary axis crossing at K≈6, ω≈±√2
omega_c = np.sqrt(2)
fig.add_trace(go.Scatter(
x=[0, 0], y=[omega_c, -omega_c],
mode="markers",
name="Crossing (K≈6, ω≈±√2)",
marker=dict(color=TEAL, size=11, symbol="circle-open", line=dict(width=2.5)),
hovertemplate="±j√2 (K≈6)<extra></extra>",
))
fig.update_layout(
xaxis=dict(
title="Real",
range=[-4, 1.5],
zeroline=True,
zerolinecolor=GRID,
zerolinewidth=1,
),
yaxis=dict(
title="Imaginary",
range=[-5, 5],
zeroline=True,
zerolinecolor=GRID,
zerolinewidth=1,
),
legend=dict(orientation="h", y=1.08),
margin=dict(t=40, b=60, l=70, r=40),
height=600,
)
return fig
if __name__ == "__main__":
generate()
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